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	<title>Learn Math The Easiest</title>
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	<link>http://watchmath.com/vlog</link>
	<description></description>
	<lastBuildDate>Sun, 17 Jan 2010 12:52:26 +0000</lastBuildDate>
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		<item>
		<title>Universal of a square</title>
		<link>http://watchmath.com/vlog/?p=1341</link>
		<comments>http://watchmath.com/vlog/?p=1341#comments</comments>
		<pubDate>Sat, 16 Jan 2010 14:44:50 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[homological algebra]]></category>
		<category><![CDATA[universal]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1341</guid>
		<description><![CDATA[Let and be left -modules. We say that is a universal of the square diagram if whenever we have another diagram there exist a unique homomorphism such that the following diagram commutes We want to show that the universal is unique of  to isomorphism, i.e., if we have two universal and then they are isomorphic. [...]]]></description>
			<content:encoded><![CDATA[<p>Let <img src="http://watchmath.com/vlog/wp-content/cache/tex_e6a4a55b346aae693e5a374a1139a489.png"  class="tex" align="absmiddle" title="P,M_1,M_2" /> and <img src="http://watchmath.com/vlog/wp-content/cache/tex_911726f38cf8de496f391803261e4738.png"  class="tex" align="absmiddle" title="N" /> be left <img src="http://watchmath.com/vlog/wp-content/cache/tex_dbd8929a74d3afc5e92220c2db42d8b6.png"  class="tex" align="absmiddle" title="R" />-modules. We say that <img src="http://watchmath.com/vlog/wp-content/cache/tex_ac6ec3224b6a74b923a61c92bf77d746.png"  class="tex" align="absmiddle" title="P" /> is a universal of the square diagram</p>
<p><center><img src="http://watchmath.com/vlog/wp-content/cache/tex_66b869e75a8746a74f9a6e8ca4e66e13.png"  class="tex" align="absmiddle" title="\xymatrix{P\ar[r]^{g_1}\ar[d]_{g_2}&amp;M_1\ar[d]^{f_1}\\M_2\ar[r]_{f_2}&amp;N}" /></center></p>
<p>if whenever we have another diagram</p>
<p><center><img src="http://watchmath.com/vlog/wp-content/cache/tex_746bd2ff84d868dee4e1b758be399a11.png"  class="tex" align="absmiddle" title="\xymatrix{P'\ar[r]^{g'_1}\ar[d]_{g'_2}&amp;M_1\ar[d]^{f_1}\\M_2\ar[r]_{f_2}&amp;N}" /></center></p>
<p>there exist a unique homomorphism <img src="http://watchmath.com/vlog/wp-content/cache/tex_514c3f16f23fc0ae9d5c3831e8feec2c.png"  class="tex" align="absmiddle" title="h:P'\to P" /> such that the following diagram commutes</p>
<p><center><img src="http://watchmath.com/vlog/wp-content/cache/tex_45cbbf98b240d7650f6ce528628c7cc1.png"  class="tex" align="absmiddle" title="\xymatrix@C+2em@R+2em{P' \ar@/_5pt/[ddr]_{g'_2} \ar@/^5pt/[drr]^{g'_1} \ar@{..&gt;}[dr]^h&amp; &amp; \\&amp; P \ar[d]_(0.4){g_2} \ar[r]^(0.4){g_1} &amp; M_1 \ar[d]^{f_1}\\&amp; M_2 \ar[r]_{f_2} &amp; N}" /></center></p>
<p>We want to show that the universal is unique of  to isomorphism, i.e., if we have two universal <img src="http://watchmath.com/vlog/wp-content/cache/tex_ac6ec3224b6a74b923a61c92bf77d746.png"  class="tex" align="absmiddle" title="P" /> and <img src="http://watchmath.com/vlog/wp-content/cache/tex_eb966765668082f52448269f4c9b1be1.png"  class="tex" align="absmiddle" title="P'" /> then they are isomorphic. Since <img src="http://watchmath.com/vlog/wp-content/cache/tex_ac6ec3224b6a74b923a61c92bf77d746.png"  class="tex" align="absmiddle" title="P" /> is a universal we have an <img src="http://watchmath.com/vlog/wp-content/cache/tex_514c3f16f23fc0ae9d5c3831e8feec2c.png"  class="tex" align="absmiddle" title="h:P'\to P" /> that makes the above diagram commutes. Similarly, considering <img src="http://watchmath.com/vlog/wp-content/cache/tex_eb966765668082f52448269f4c9b1be1.png"  class="tex" align="absmiddle" title="P'" /> as a universal, we have <img src="http://watchmath.com/vlog/wp-content/cache/tex_e2ff90156f0046ae52e11430b5169b3a.png"  class="tex" align="absmiddle" title="h':P\to P'" /> that make the diagram</p>
<p><center><img src="http://watchmath.com/vlog/wp-content/cache/tex_02637d4c343a78589972b8cd672f6c68.png"  class="tex" align="absmiddle" title="\xymatrix@C+2em@R+2em{ P\ar@/_5pt/[ddr]_{g_2} \ar@/^5pt/[drr]^{g_1} \ar@{..&gt;}[dr]^{h'}&amp; &amp; \\&amp; P '\ar[d]_(0.4){g'_2} \ar[r]^(0.4){g'_1} &amp; M_1 \ar[d]^{f_1}\\&amp; M_2 \ar[r]_{f_2} &amp; N}" /></center></p>
<p>commmutes. Combining the two diagrams above we have the following commutative diagram</p>
<p><center><img src="http://watchmath.com/vlog/wp-content/cache/tex_e8ebbc4a3cc739786e5770b96c85eab2.png"  class="tex" align="absmiddle" title="\xymatrix@C+2em@R+2em{P \ar@/_5pt/[ddr]_{g_2} \ar@/^5pt/[drr]^{g_1} \ar@{..&gt;}[dr]^{h'\circ h}&amp; &amp; \\&amp; P \ar[d]_(0.4){g_2} \ar[r]^(0.4){g_1} &amp; M_1 \ar[d]^{f_1}\\&amp; M_2 \ar[r]_{f_2} &amp; N}" /></center></p>
<p>On the other hand we have the following obvious diagram</p>
<p><center><img src="http://watchmath.com/vlog/wp-content/cache/tex_e8ebbc4a3cc739786e5770b96c85eab2.png"  class="tex" align="absmiddle" title="\xymatrix@C+2em@R+2em{P \ar@/_5pt/[ddr]_{g_2} \ar@/^5pt/[drr]^{g_1} \ar@{..&gt;}[dr]^{h'\circ h}&amp; &amp; \\&amp; P \ar[d]_(0.4){g_2} \ar[r]^(0.4){g_1} &amp; M_1 \ar[d]^{f_1}\\&amp; M_2 \ar[r]_{f_2} &amp; N}" /></center></p>
<p>By uniqueness, it follows that <img src="http://watchmath.com/vlog/wp-content/cache/tex_f17cb6dfa5a0bbe115171543d56ab846.png"  class="tex" align="absmiddle" title="h'\circ h = 1_P" /> and by similar argument, one can show that <img src="http://watchmath.com/vlog/wp-content/cache/tex_090f1a1aea71000193d8861eba71b59d.png"  class="tex" align="absmiddle" title="h\circ h'=1_{P'}" />. Therefore <img src="http://watchmath.com/vlog/wp-content/cache/tex_5358051ec001837ce46e478747ab836b.png"  class="tex" align="absmiddle" title="h" /> and <img src="http://watchmath.com/vlog/wp-content/cache/tex_c62720f584dfba0179da7d742dca8689.png"  class="tex" align="absmiddle" title="h'" /> are isomorphisms and therefore <img src="http://watchmath.com/vlog/wp-content/cache/tex_ac6ec3224b6a74b923a61c92bf77d746.png"  class="tex" align="absmiddle" title="P" /> is isomorphic to <img src="http://watchmath.com/vlog/wp-content/cache/tex_eb966765668082f52448269f4c9b1be1.png"  class="tex" align="absmiddle" title="P'" />.</p>
]]></content:encoded>
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		<slash:comments>1</slash:comments>
		</item>
		<item>
		<title>Solution of MMM#38</title>
		<link>http://watchmath.com/vlog/?p=926</link>
		<comments>http://watchmath.com/vlog/?p=926#comments</comments>
		<pubDate>Mon, 02 Nov 2009 18:10:41 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Equation]]></category>
		<category><![CDATA[Math Monday Madness]]></category>
		<category><![CDATA[Math Problem]]></category>
		<category><![CDATA[Math Puzzle]]></category>
		<category><![CDATA[MMM]]></category>
		<category><![CDATA[Problem Solving]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=926</guid>
		<description><![CDATA[MMM #38: Prove or disprove: The product of any four consecutive integers is always one less than a perfect square. Don’t assume the integers are all positive. Any four consecutive integers can be written as . The product of these numbers is Therefore the statement always true.]]></description>
			<content:encoded><![CDATA[<p>MMM #38:</p>
<blockquote><p><em>Prove or disprove: The product of any four consecutive integers is always one less than a perfect square.<br />
Don’t assume the integers are all positive.</em></p></blockquote>
<p>Any four consecutive integers can be written as <img src="http://watchmath.com/vlog/wp-content/cache/tex_da4afd383a49758b4faf50e553e4ed99.png"  class="tex" align="absmiddle" title="n-2,n-1,n,n+1" />. The product of these numbers is</p>
<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_7c519fa8c49982396e3a1c11bfbea6d4.png"  class="tex" align="absmiddle" title="\begin{align*}(n-1)n(n+1)(n-2)&amp;=(n^2-n)(n^2-n-2)&amp;\\&amp;=\left[(n^2-n-1)+1\right]\left[(n^2-n-1)-1\right]\\&amp;=(n^2-n-1)^2-1.\end{align*}" /></p>
<p>Therefore the statement always true.</p>
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		<item>
		<title>New Installation : Latex on Blogger/Blogspot</title>
		<link>http://watchmath.com/vlog/?p=1244</link>
		<comments>http://watchmath.com/vlog/?p=1244#comments</comments>
		<pubDate>Fri, 09 Oct 2009 05:11:56 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Latex]]></category>
		<category><![CDATA[Latex On Blogger]]></category>
		<category><![CDATA[blogger]]></category>
		<category><![CDATA[Latex on Blogspot]]></category>
		<category><![CDATA[mathtex]]></category>
		<category><![CDATA[TeX]]></category>
		<category><![CDATA[Typesetting]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1244</guid>
		<description><![CDATA[This is the updated procedure of how to install latex on your Blogger. What&#8217;s New? The script located in a more stable location (in google server) rather than using watchmath.com server (which sometimes down for some unknown reason). New script, adapting the preference of either using \textstyle of \displaystyle as the default mode. More flexibility. [...]]]></description>
			<content:encoded><![CDATA[<p>This is the updated procedure of how to install latex on your Blogger.</p>
<h2>What&#8217;s New?</h2>
<ul>
<li>The script located in a more stable location (in google server) rather than using watchmath.com server (which sometimes down for some unknown reason).</li>
<li>New script, adapting the preference of either using \textstyle of \displaystyle as the default mode.</li>
<li>More flexibility. Customization on default size, color, adding latex packages and defining new commands.</li>
</ul>
<h2>How To Install</h2>
<p>Use the instruction <a href="http://watchmath.com/vlog/?p=438">here</a>, but in step one copy and use instead the following script.</p>

<div class="wp_syntax"><div class="code"><pre class="javascript" style="font-family:monospace;">&lt;script src=&quot;http://latexonblogger.googlegroups.com/web/mathtex3.js?hl=en&amp;amp;gda=R9ZVlD4AAABbAsbN4i7hi2ZFNZpVWCi9LFztQtuc529xoR6FBh351sAOXLBpscdVgFPClVlUxUzjsKXVs-X7bdXZc5buSfmx&quot; type=&quot;text/javascript&quot;&gt;&lt;/script&gt;
<span style="color: #339933;">&lt;</span>script type<span style="color: #339933;">=</span><span style="color: #3366CC;">&quot;text/javascript&quot;</span><span style="color: #339933;">&gt;</span>window.<span style="color: #660066;">mathPreamble</span> <span style="color: #339933;">=</span>
 <span style="color: #3366CC;">'<span style="color: #000099; font-weight: bold;">\\</span>newcommand{<span style="color: #000099; font-weight: bold;">\\</span>RR}{<span style="color: #000099; font-weight: bold;">\\</span>mathbb{R}}<span style="color: #000099; font-weight: bold;">\\</span>usepackage[usenames]{color}<span style="color: #000099; font-weight: bold;">\\</span>color{} <span style="color: #000099; font-weight: bold;">\\</span>gammacorrection{1.3}<span style="color: #000099; font-weight: bold;">\\</span>png <span style="color: #000099; font-weight: bold;">\\</span>normal '</span><span style="color: #339933;">;</span>replaceMath<span style="color: #009900;">&#40;</span> document.<span style="color: #660066;">body</span> <span style="color: #009900;">&#41;</span><span style="color: #339933;">;&lt;/</span>script<span style="color: #339933;">&gt;</span>
&nbsp;
&lt;center&gt;
&lt;a href=&quot;http://www.watchmath.com&quot;&gt;
&lt;img alt=&quot;&quot; src=&quot;http://www.watchmath.com/images/formula.png&quot; width=&quot;100&quot;&gt;&lt;/a&gt;
&lt;br&gt;
&lt;a href=&quot;http://watchmath.com/vlog/?p=1244&quot;&gt;
Install LaTeX?&lt;/a&gt;&lt;/center&gt;</pre></div></div>

<h2>Usage</h2>
<ul>
<li>Use <font size="3" face="monospace" color="Green">$\LaTeX$</font> in order to get an inline math in \textstyle mode. For example if you type <font size="3" face="monospace" color="Green">$\sum_{i=1}^nx_i$</font> (in blogger) you get <img src="http://watchmath.com/vlog/wp-content/cache/tex_f9edb46e6f8b148bf2d98d4aa373f3df.png"  class="tex" align="absmiddle" title="\textstyle\sum_{i=1}^nx_i" />.</li>
<li>Use $$\LaTeX $$ to gen an inline math in \displaystyle&nbsp; mode. For example if you type $<font size="3" face="monospace" color="Green">$\sum_{i=1}^nx_i$</font>$&nbsp; (in blogger) you get <img src="http://watchmath.com/vlog/wp-content/cache/tex_761795087b82f9f4297c8b218c49f50a.png"  class="tex" align="absmiddle" title="\displaystyle\sum_{i=1}^nx_i" />.</li>
<li>Use <font size="3" face="monospace" color="Green">\[\LaTeX\]</font> to get a math symbol written in a new line and aligned center. For example if you type <font size="3" face="monospace" color="Green">\[\sum_{i=1}^nx_i\]</font>&nbsp; (in blogger) you get <center><img src="http://watchmath.com/vlog/wp-content/cache/tex_3bb9c0c07ba40d041daae9f20bc1eeb7.png"  class="tex" align="absmiddle" title="\sum_{i=1}^nx_i" /></center>.</li>
</ul>
<h2>Customization</h2>
<p>Modify</p>

<div class="wp_syntax"><div class="code"><pre class="javascript" style="font-family:monospace;">window.<span style="color: #660066;">mathPreamble</span> <span style="color: #339933;">=</span>
 <span style="color: #3366CC;">'<span style="color: #000099; font-weight: bold;">\\</span>newcommand{<span style="color: #000099; font-weight: bold;">\\</span>RR}{<span style="color: #000099; font-weight: bold;">\\</span>mathbb{R}}<span style="color: #000099; font-weight: bold;">\\</span>usepackage[usenames]{color}<span style="color: #000099; font-weight: bold;">\\</span>color{} <span style="color: #000099; font-weight: bold;">\\</span>gammacorrection{1}<span style="color: #000099; font-weight: bold;">\\</span>png <span style="color: #000099; font-weight: bold;">\\</span>normal '</span><span style="color: #339933;">;</span></pre></div></div>

<p>in the script above. All extra command will be written inside the quotation marks.</p>
<ul>
<li>Color: To change the default color, replace \\color{} by \\color{colorname} where colorname is one of the entries in the following table <center><img src="http://watchmath.com/vlog/wp-content/cache/tex_94aa14dfc03f93faae3dfd456fba517e.png"  class="tex" align="absmiddle" title="\begin{tabular}{|l|l|l|l|}\hline{\color{Apricot} Apricot}&amp;{\color{Aquamarine} Aquamarine}&amp;{\color{Bittersweet} Bittersweet}&amp;{\color{Black} Black}\\ \hline{\color{Blue} Blue}&amp;{\color{BlueGreen} BlueGreen}&amp;{\color{BlueViolet} BlueViolet}&amp;{\color{BrickRed} BrickRed}\\ \hline{\color{Brown} Brown}&amp;{\color{BurntOrange} BurntOrange}&amp;{\color{CadetBlue} CadetBlue}&amp;{\color{CarnationPink} CarnationPink}\\ \hline{\color{Cerulean} Cerulean}&amp;{\color{CornflowerBlue} CornflowerBlue}&amp;{\color{Cyan} Cyan}&amp;{\color{Dandelion} Dandelion}\\ \hline{\color{DarkOrchid} DarkOrchid}&amp;{\color{Emerald} Emerald}&amp;{\color{ForestGreen} ForestGreen}&amp;{\color{Fuchsia} Fuchsia}\\ \hline{\color{Goldenrod} Goldenrod}&amp;{\color{Gray} Gray}&amp;{\color{Green} Green}&amp;{\color{GreenYellow} GreenYellow}\\ \hline{\color{JungleGreen} JungleGreen}&amp;{\color{Lavender} Lavender}&amp;{\color{LimeGreen} LimeGreen}&amp;{\color{Magenta} Magenta}\\ \hline{\color{Mahogany} Mahogany}&amp;{\color{Maroon} Maroon}&amp;{\color{Melon} Melon}&amp;{\color{MidnightBlue} MidnightBlue}\\ \hline{\color{Mulberry} Mulberry}&amp;{\color{NavyBlue} NavyBlue}&amp;{\color{OliveGreen} OliveGreen}&amp;{\color{Orange} Orange}\\ \hline{\color{OrangeRed} OrangeRed}&amp;{\color{Orchid} Orchid}&amp;{\color{Peach} Peach}&amp;{\color{Periwinkle} Periwinkle}\\ \hline{\color{PineGreen} PineGreen}&amp;{\color{Plum} Plum}&amp;{\color{ProcessBlue} ProcessBlue}&amp;{\color{Purple} Purple}\\ \hline{\color{RawSienna} RawSienna}&amp;{\color{Red} Red}&amp;{\color{RedOrange} RedOrange}&amp;{\color{RedViolet} RedViolet}\\ \hline{\color{Rhodamine} Rhodamine}&amp;{\color{RoyalBlue} RoyalBlue}&amp;{\color{RoyalPurple} RoyalPurple}&amp;{\color{RubineRed} RubineRed}\\ \hline{\color{Salmon} Salmon}&amp;{\color{SeaGreen} SeaGreen}&amp;{\color{Sepia} Sepia}&amp;{\color{SkyBlue} SkyBlue}\\ \hline{\color{SpringGreen} SpringGreen}&amp;{\color{Tan} Tan}&amp;{\color{TealBlue} TealBlue}&amp;{\color{Thistle} Thistle}\\ \hline{\color{Turquoise} Turquoise}&amp;{\color{Violet} Violet}&amp;{\color{VioletRed} VioletRed}&amp;{\color{White} White}\\ \hline{\color{WildStrawberry} WildStrawberry}&amp;{\color{Yellow} Yellow}&amp;{\color{YellowGreen} YellowGreen}&amp;{\color{YellowOrange} YellowOrange}\\ \hline\end{tabular}" /></center></li>
<li>Size: by default the latex output is in normal size. To change the default size, change \\normal by one of the following: \\tiny, \\scriptsize,\\large,\\Large,\\huge.</li>
<li>Latex Package: by default the package \\usepackage[usenames]{color} is included. You can add more package by adding&nbsp; \\usepackage{packagename}. To test whether a particular package is supported, type \usepackage{packagename} (use only one backslash this time) in an inline command. For example, fancybox package is supported by mathtex because if you type <font size="3" face="monospace" color="Green">$\usepackage{fancybox}\shadowbox{This is fancy}$</font> you will get <img src="http://watchmath.com/vlog/wp-content/cache/tex_e698b51b8d560243bd6590f19c684ad0.png"  class="tex" align="absmiddle" title="\usepackage{fancybox}\shadowbox{This is fancy}" />. Here is a list of package that I know work with mathtex: xypic, calrsfs, calligra, fancybox,epic,eepic(?). Let me know if you find another package that works with mathtex.</li>
<li>Newcommand: we have included an example how to define a new command in the script above. We use \\newcommand{\\RR}{\\mathbb{R}} to define a command \RR. Typing <font size="3" face="monospace" color="Green">$\RR$</font> (in blogger) will give you the same result as typing <font size="3" face="monospace" color="Green">$\mathbb{R}$</font>, i.e., you get <img src="http://watchmath.com/vlog/wp-content/cache/tex_4c93702f4ce95b1ed6dcfc136022a4ce.png"  class="tex" align="absmiddle" title="\mathbb{R}" />.</li>
<li>Darkness: \\gammacorrection{1.3} controls the darkness of the output. Do&nbsp; experiments to get the best result by changing 1.3 into any number you like.</li>
</ul>
<h2>Demo?</h2>
<p>Visit <a href="http://www.watchmath.blogspot.com">http://www.watchmath.blogspot.com</a></p>
<div style="margin-top: 10px; height: 15px;" class="zemanta-pixie"><a class="zemanta-pixie-a" href="http://reblog.zemanta.com/zemified/0124ad48-ba6b-4db3-947d-18231f9ce668/" title="Reblog this post [with Zemanta]"><img style="border: medium none ; float: right;" class="zemanta-pixie-img" src="http://img.zemanta.com/reblog_e.png?x-id=0124ad48-ba6b-4db3-947d-18231f9ce668" alt="Reblog this post [with Zemanta]"></a><span class="zem-script more-related pretty-attribution"><script type="text/javascript" src="http://static.zemanta.com/readside/loader.js" defer="defer"></script></span></div>
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		</item>
		<item>
		<title>Solution to Worksheet 9 (Lines)</title>
		<link>http://watchmath.com/vlog/?p=1236</link>
		<comments>http://watchmath.com/vlog/?p=1236#comments</comments>
		<pubDate>Mon, 05 Oct 2009 13:24:27 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Algebra]]></category>
		<category><![CDATA[MA109]]></category>
		<category><![CDATA[line]]></category>
		<category><![CDATA[linear equation]]></category>
		<category><![CDATA[Perpendicular]]></category>
		<category><![CDATA[Slope]]></category>
		<category><![CDATA[Y-intercept]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1236</guid>
		<description><![CDATA[Find the slope of the line through and 1. 2. Find an equation of the line that satisfies the given conditions. 3. Through ; slope 1 4. Through and 5. Slope 3; y-intercept -2 6. Through ; parallel to the -axis 7. Through ; parallel to the line 8. Through ; perpendicular to the line [...]]]></description>
			<content:encoded><![CDATA[<p>Find the slope of the line through <img src="http://watchmath.com/vlog/wp-content/cache/tex_ac6ec3224b6a74b923a61c92bf77d746.png"  class="tex" align="absmiddle" title="P" /> and <img src="http://watchmath.com/vlog/wp-content/cache/tex_e6ee9927f584e42ec70b27a146b4b32c.png"  class="tex" align="absmiddle" title="Q" /><br />
1. <img src="http://watchmath.com/vlog/wp-content/cache/tex_129af1dead0ee52c79f031cf7b863760.png"  class="tex" align="absmiddle" title="P(2,-5),\,Q(-4,3)" /></p>
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				<input type="button" onclick="tiny_spoiler('Solutionvauwutlysf')" id="Solutionvauwutlysf_button" value="+" />
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<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_3dd3fa009a4ebc125e651da6b9cbc002.png"  class="tex" align="absmiddle" title="m=\frac{3+5}{-4-2}=\frac{8}{-6}=-\frac{4}{3}" />.</p>
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<p>2. <img src="http://watchmath.com/vlog/wp-content/cache/tex_3224a6a73751f9e0a06aaadd16861b0f.png"  class="tex" align="absmiddle" title="P(1,-3),\,Q(-1,6)" /></p>
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				<input type="button" onclick="tiny_spoiler('Solutioncvtnouyvoj')" id="Solutioncvtnouyvoj_button" value="+" />
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<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_3f81c84cb486dc2b3086e417e81e82ed.png"  class="tex" align="absmiddle" title="m=\frac{6-1}{-1+3}=\frac{5}{2}" />.</p>
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<p>Find an equation of the line that satisfies the given conditions.<br />
3. Through <img src="http://watchmath.com/vlog/wp-content/cache/tex_44f11f0e6ff16a4901bf483324bd6434.png"  class="tex" align="absmiddle" title="(2,3)" />; slope 1</p>
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<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_b0af9ae57b7a6bf317fde5426a7cbd62.png"  class="tex" align="absmiddle" title="y-3=1(x-2)" /></p>
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<p>4. Through <img src="http://watchmath.com/vlog/wp-content/cache/tex_f413488f0cbe4a7957e20735533c1c43.png"  class="tex" align="absmiddle" title="(2,1)" /> and <img src="http://watchmath.com/vlog/wp-content/cache/tex_f26409c9e5511d2b3cdbf812d68e5b89.png"  class="tex" align="absmiddle" title="(1,6)" /></p>
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<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_c1d1662882416e6b0a93e73335d1c682.png"  class="tex" align="absmiddle" title="m=\frac{6-1}{1-2}=-5" />. Hence</p>
<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_b5e81497d2488b41e8487a0464bab2f3.png"  class="tex" align="absmiddle" title="y-1=5(x-2)" /></p>
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<p>5. Slope 3; y-intercept -2</p>
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<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_cf4e3fbbcd46f786670979ba5d939a65.png"  class="tex" align="absmiddle" title="y=3x-2" /></p>
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<p>6. Through <img src="http://watchmath.com/vlog/wp-content/cache/tex_5c837de886f90cfe2ba711cc94789e2e.png"  class="tex" align="absmiddle" title="(4,5)" />; parallel to the <img src="http://watchmath.com/vlog/wp-content/cache/tex_2737227b9b28a8b5f3d0fc7f042a7915.png"  class="tex" align="absmiddle" title="y" />-axis</p>
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				<input type="button" onclick="tiny_spoiler('Spoilerivqkjxmldz')" id="Spoilerivqkjxmldz_button" value="+" />
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<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_58c2a09d7033bd0d6986c998d8ecae9d.png"  class="tex" align="absmiddle" title="x=4" /></p>
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<p>7. Through <img src="http://watchmath.com/vlog/wp-content/cache/tex_b8d17070f56eb50b4dc2a314ace22e6f.png"  class="tex" align="absmiddle" title="(1,-6)" />; parallel to the line <img src="http://watchmath.com/vlog/wp-content/cache/tex_328ecd00faa7cee77ef1e33fc16716e9.png"  class="tex" align="absmiddle" title="x+2y=6" /></p>
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<p>The equation <img src="http://watchmath.com/vlog/wp-content/cache/tex_328ecd00faa7cee77ef1e33fc16716e9.png"  class="tex" align="absmiddle" title="x+2y=6" /> can be rewritten as <img src="http://watchmath.com/vlog/wp-content/cache/tex_d5a8714d847343f5b82a7f5e8b2b27e8.png"  class="tex" align="absmiddle" title="y=-(1/2)x+3" />. Hence the slope is <img src="http://watchmath.com/vlog/wp-content/cache/tex_0da3df4c144757fa7960f3592d969b22.png"  class="tex" align="absmiddle" title="-1/2" />.</p>
<p>Since the line through <img src="http://watchmath.com/vlog/wp-content/cache/tex_b8d17070f56eb50b4dc2a314ace22e6f.png"  class="tex" align="absmiddle" title="(1,-6)" /> is parallel then the slope also <img src="http://watchmath.com/vlog/wp-content/cache/tex_0da3df4c144757fa7960f3592d969b22.png"  class="tex" align="absmiddle" title="-1/2" />. It follows that the line is given by the equation</p>
<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_439364dc4c47a54480f5b54826001646.png"  class="tex" align="absmiddle" title="y+6=-(1/2)(x-1)" /></p>
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<p>8. Through <img src="http://watchmath.com/vlog/wp-content/cache/tex_337e36f390ef33e6b7c2d614ad85efbc.png"  class="tex" align="absmiddle" title="(-1,-2)" />; perpendicular to the line <img src="http://watchmath.com/vlog/wp-content/cache/tex_6260ef115c7f84686c3c2d66b61c05a4.png"  class="tex" align="absmiddle" title="2x+5y+8=0" /></p>
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				<input type="button" onclick="tiny_spoiler('Solutionaweylfkues')" id="Solutionaweylfkues_button" value="+" />
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<p>The equation <img src="http://watchmath.com/vlog/wp-content/cache/tex_6260ef115c7f84686c3c2d66b61c05a4.png"  class="tex" align="absmiddle" title="2x+5y+8=0" /> can be rewritten as <img src="http://watchmath.com/vlog/wp-content/cache/tex_ed9b3d4fe26acec5dc35be8b67618677.png"  class="tex" align="absmiddle" title="y=-(2/5)x-8" />. So its slope is <img src="http://watchmath.com/vlog/wp-content/cache/tex_6f577f64555fb407498cd9234190eabd.png"  class="tex" align="absmiddle" title="-2/5" /> and the line that perpendicular to it has slope <img src="http://watchmath.com/vlog/wp-content/cache/tex_bc5564071cc243ec51bff7329b36db58.png"  class="tex" align="absmiddle" title="5/2" />.</p>
<p>Therefore the equation of line that we are looking for is</p>
<p><img src="http://watchmath.com/vlog/wp-content/cache/tex_b0e0b23086c10fd7c7cd70ee941e384c.png"  class="tex" align="absmiddle" title="y+2=(5/2)(x+1)" /></p>
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<p>Find the slope and y-intercept of the given line<br />
9. <img src="http://watchmath.com/vlog/wp-content/cache/tex_0e04bf263deda9319196bc288db32260.png"  class="tex" align="absmiddle" title="3x-2y=12" /></p>
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<p>The equation can be rewritten as <img src="http://watchmath.com/vlog/wp-content/cache/tex_875201e4dfa240197cb8f737b766ba9a.png"  class="tex" align="absmiddle" title="y=(3/2)x-6" />.</p>
<p>Hence the slope is <img src="http://watchmath.com/vlog/wp-content/cache/tex_a8498b121b273038283d4c501e4b1d78.png"  class="tex" align="absmiddle" title="3/2" /> and the <img src="http://watchmath.com/vlog/wp-content/cache/tex_2737227b9b28a8b5f3d0fc7f042a7915.png"  class="tex" align="absmiddle" title="y" />-intercept is <img src="http://watchmath.com/vlog/wp-content/cache/tex_4edede90547796307d1583b7625ca2ae.png"  class="tex" align="absmiddle" title="(0,-6)" />.</p>
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<p>10. <img src="http://watchmath.com/vlog/wp-content/cache/tex_20c6ff7b895739fd0550da45a78739f9.png"  class="tex" align="absmiddle" title="-3x-5y+30=0" /></p>
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<p>Rewrite the equation as <img src="http://watchmath.com/vlog/wp-content/cache/tex_e470732d548204157ce8d9ff23edd4d4.png"  class="tex" align="absmiddle" title="y=-(3/5)x+6" />.</p>
<p>Hence the slope is <img src="http://watchmath.com/vlog/wp-content/cache/tex_a30c843b36e169b9ee601550accaf2cf.png"  class="tex" align="absmiddle" title="-3/5" /> and the <img src="http://watchmath.com/vlog/wp-content/cache/tex_2737227b9b28a8b5f3d0fc7f042a7915.png"  class="tex" align="absmiddle" title="y" />-intercept is <img src="http://watchmath.com/vlog/wp-content/cache/tex_eff7b6bc05adf43ce12faa5c7707b366.png"  class="tex" align="absmiddle" title="(0,6)" />.</p>
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		<title>Worksheet 5 (Inequalities) Solution</title>
		<link>http://watchmath.com/vlog/?p=1187</link>
		<comments>http://watchmath.com/vlog/?p=1187#comments</comments>
		<pubDate>Wed, 16 Sep 2009 15:15:55 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Algebra]]></category>
		<category><![CDATA[MA109]]></category>
		<category><![CDATA[Inequalities]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1187</guid>
		<description><![CDATA[Solve the linear inequality. Express the solution using interval notation. 1.]]></description>
			<content:encoded><![CDATA[<p>Solve the linear inequality. Express the solution using interval notation.<br />
1. <img src="http://watchmath.com/vlog/wp-content/cache/tex_7cee9a9c84ad5112f549baf94d39c448.png"  class="tex" align="absmiddle" title="3x+11<5" /><br />
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<img src="http://watchmath.com/vlog/wp-content/cache/tex_40ef5537066eabc1a76c4a5ec71613fa.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
3x+11&#038;<5\\<br />
3x&#038;<-6\\<br />
x&#038;<-2<br />
\end{align*}" /><br />
Therefore <img src="http://watchmath.com/vlog/wp-content/cache/tex_90a0f149844a5d36c7722b5dc3fe6147.png"  class="tex" align="absmiddle" title="x" /> is in the interval <img src="http://watchmath.com/vlog/wp-content/cache/tex_9ad584558f046a927911b7d35297f527.png"  class="tex" align="absmiddle" title="(-\infty,-2)" />.<br />

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2. <img src="http://watchmath.com/vlog/wp-content/cache/tex_050a1ea15037840474f24f7b76474061.png"  class="tex" align="absmiddle" title="\frac{2}{5}x+1<\frac{1}{5}-2x" /><br />
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Multiply both sides by 5, we have <img src="http://watchmath.com/vlog/wp-content/cache/tex_4d1af90b7c22fc0f4d8b5b1dd2ab1b11.png"  class="tex" align="absmiddle" title="2x+5<1-10x" /><br />
Now<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_15862dcfed0905db6732c2512f1b907d.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
2x+5&#038;<1-10x\\<br />
12x+5&#038;<1\\<br />
12x&#038;<-4\\<br />
x&#038;<-4/12\\<br />
x&#038;<-1/3<br />
\end{align*}" /><br />
So <img src="http://watchmath.com/vlog/wp-content/cache/tex_90a0f149844a5d36c7722b5dc3fe6147.png"  class="tex" align="absmiddle" title="x" /> is in <img src="http://watchmath.com/vlog/wp-content/cache/tex_939a0854a0c2ccd8089d8b7906ba0258.png"  class="tex" align="absmiddle" title="(-\infty,-1/3)" />.<br />

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3. <img src="http://watchmath.com/vlog/wp-content/cache/tex_9c0a7487569eefbf478f799fe2ff23a9.png"  class="tex" align="absmiddle" title="2(7x-3)\leq 12x+16" /><br />
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Divide both sides by 2, we have<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_4d324ecfee382910fe79091abdbec8ed.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
7x-3&#038;\leq 6x+8\\<br />
x-3&#038;\leq 8\\<br />
x&#038;\leq 11<br />
\end{align*}" /><br />
So <img src="http://watchmath.com/vlog/wp-content/cache/tex_90a0f149844a5d36c7722b5dc3fe6147.png"  class="tex" align="absmiddle" title="x" /> is in <img src="http://watchmath.com/vlog/wp-content/cache/tex_9fb4133e2a5fc9e8b85c027f319ea63e.png"  class="tex" align="absmiddle" title="(-\infty,11]" />.<br />

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4. <img src="http://watchmath.com/vlog/wp-content/cache/tex_4f90e74bbab2f195f971ec0f5f78e9ca.png"  class="tex" align="absmiddle" title="5\leq 3x-4\leq 14" /><br />
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Add 4 to each term, we have<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_943c3004b6f55243d61e51c7e2178fbe.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
9\leq &#038;3x\leq 18\\<br />
3\leq &#038;x\leq 6<br />
\end{align*}" /><br />
So <img src="http://watchmath.com/vlog/wp-content/cache/tex_90a0f149844a5d36c7722b5dc3fe6147.png"  class="tex" align="absmiddle" title="x" /> is in <img src="http://watchmath.com/vlog/wp-content/cache/tex_4cc475633779326e7659e054230c8190.png"  class="tex" align="absmiddle" title="[3,6]" />.<br />

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5. <img src="http://watchmath.com/vlog/wp-content/cache/tex_07bc2d8aa288d01b661b8db4c43a9a47.png"  class="tex" align="absmiddle" title="-\frac{1}{2}<\frac{4-3x}{5}\leq \frac{1}{4}" /><br />
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Multiply by 5 we have <img src="http://watchmath.com/vlog/wp-content/cache/tex_517bf975265de0027773b815b21ee90e.png"  class="tex" align="absmiddle" title="-5/2<4-3x <5/4" />. Subtract 4 to get <img src="http://watchmath.com/vlog/wp-content/cache/tex_f6949b7463313201371c1eb79ebb4f2c.png"  class="tex" align="absmiddle" title="(5/2)-4<-3x<(5/4)-4" />. The last inequality can be simplify into<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_30758f8ce5fe87a4649e98beab8b5cec.png"  class="tex" align="absmiddle" title="-13/2<-3x<11/4" />.Divide by -3 we have <img src="http://watchmath.com/vlog/wp-content/cache/tex_605ade502a2236e4ce76f8739498e40f.png"  class="tex" align="absmiddle" title="13/6>x>-11/12&#8243; /> or reading from the right to the left <img src="http://watchmath.com/vlog/wp-content/cache/tex_fe0d1f481edfe583b924e7357cff0d46.png"  class="tex" align="absmiddle" title="-11/12<x<13/6" />. Therefore the solution is <img src="http://watchmath.com/vlog/wp-content/cache/tex_e5c0c2d33f937c41f5275e4096467d09.png"  class="tex" align="absmiddle" title="(-11/12,13/6)" />.<br />

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<p>Solve the nonlinear inequality. Express the solution using interval notation.<br />
6.<img src="http://watchmath.com/vlog/wp-content/cache/tex_56873f41f6f760a0124d90aea7299797.png"  class="tex" align="absmiddle" title="(x-5)(x+4)\geq 0" /><br />
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				<input type="button" onclick="tiny_spoiler('Solutionkaotzwhvfh')" id="Solutionkaotzwhvfh_button" value="+" />
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			<div id="Solutionkaotzwhvfh"><img src="http://watchmath.com/vlog/wp-content/cache/tex_b66e3169741081e07009faf6a00b7646.png"  class="tex" align="absmiddle" title="(-\infty,-4]\cup [5,\infty)" />
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7. <img src="http://watchmath.com/vlog/wp-content/cache/tex_e4e79d68dcd4440edbeb67f80a1ffc8d.png"  class="tex" align="absmiddle" title="5x^2+3x\geq 3x^2+2" /><br />
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Rewrite the inequality as <img src="http://watchmath.com/vlog/wp-content/cache/tex_1d106c241bcfb0ff6f6bd278f2f6f11d.png"  class="tex" align="absmiddle" title="(5x^2-3x^2)+3x-2\geq 0" /><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_42dfffedea47b4d3c1a05a9000e22434.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
2x^2+3x-2&#038;\geq 0\\<br />
2x^2+4x-x-2&#038;\geq 0\\<br />
2x(x+2)-(x+2)&#038;\geq 0\\<br />
(2x-1)(x+2)&#038;\geq 0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_90a0f149844a5d36c7722b5dc3fe6147.png"  class="tex" align="absmiddle" title="x" /> is in the interval <img src="http://watchmath.com/vlog/wp-content/cache/tex_e4b08d840531eeb3b2b431bd0a1e6000.png"  class="tex" align="absmiddle" title="(-infty,-2]\cup [1/2,\infty)" /><br />

			</div>
		</fieldset><br />
8. <img src="http://watchmath.com/vlog/wp-content/cache/tex_cbe19538adab27637e9891daa8d1b4b0.png"  class="tex" align="absmiddle" title="(x+2)(x-1)(x-3)\leq 0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionzaovnqwaff')" id="Solutionzaovnqwaff_button" value="+" />
				Solution
			</legend>
			<div id="Solutionzaovnqwaff"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_b1275dd4205b2d3e086155a4b8af4b4a.png"  class="tex" align="absmiddle" title="(-infty,-2]\cup [1,3]" /><br />

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9. <img src="http://watchmath.com/vlog/wp-content/cache/tex_4d99d0c2bff15bab69e70b7cad124185.png"  class="tex" align="absmiddle" title="\frac{2x+6}{x-2}<0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionwqgljfhrbn')" id="Solutionwqgljfhrbn_button" value="+" />
				Solution
			</legend>
			<div id="Solutionwqgljfhrbn"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_c194b2d152ae13f89dd5eabd61e84673.png"  class="tex" align="absmiddle" title="(-3,2)" /><br />

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		</fieldset></p>
<p>10. <img src="http://watchmath.com/vlog/wp-content/cache/tex_36494f061a5d9eab262add828f9244b3.png"  class="tex" align="absmiddle" title="3x<x/(x+1)" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Spoilerynfjojcyir')" id="Spoilerynfjojcyir_button" value="+" />
				Spoiler
			</legend>
			<div id="Spoilerynfjojcyir">See the lecture note
			</div>
		</fieldset></p>
]]></content:encoded>
			<wfw:commentRss>http://watchmath.com/vlog/?feed=rss2&amp;p=1187</wfw:commentRss>
		<slash:comments>0</slash:comments>
		</item>
		<item>
		<title>Worked Problems (Another Type Equations)</title>
		<link>http://watchmath.com/vlog/?p=1166</link>
		<comments>http://watchmath.com/vlog/?p=1166#comments</comments>
		<pubDate>Mon, 14 Sep 2009 13:22:24 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Algebra]]></category>
		<category><![CDATA[MA109]]></category>
		<category><![CDATA[Equation of Quadratic Type]]></category>
		<category><![CDATA[Equation with Radicals]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1166</guid>
		<description><![CDATA[Find all real solutions of the equation. 1. 2. 3. 4. 5. 6. 7. 8. 9. 10.]]></description>
			<content:encoded><![CDATA[<p>Find all real solutions of the equation.<br />
1. <img src="http://watchmath.com/vlog/wp-content/cache/tex_5acedb4314f39db9f2222aa63aa17f5f.png"  class="tex" align="absmiddle" title="x^4+64x=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionxhrldfczgi')" id="Solutionxhrldfczgi_button" value="+" />
				Solution
			</legend>
			<div id="Solutionxhrldfczgi"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_163f0616afa3c54e25aa0dc9be47bbdc.png"  class="tex" align="absmiddle" title="x(x^3+64)=0" />. Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_1065700e28e0a76739a25ae46ed7bad4.png"  class="tex" align="absmiddle" title="x=0" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_89274b5b353e5d332a9cb13707eaf217.png"  class="tex" align="absmiddle" title="x^3+64=0" />. The last equation is equivalent to <img src="http://watchmath.com/vlog/wp-content/cache/tex_9ea69d9ddca499ad72ef9e7231525f30.png"  class="tex" align="absmiddle" title="x^3=-64\Leftrightarrow x=-4" />.<br />
So the solutions are <img src="http://watchmath.com/vlog/wp-content/cache/tex_f5b01643800f146275de0fe882e16859.png"  class="tex" align="absmiddle" title="x=0,-4" />.<br />

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2. <img src="http://watchmath.com/vlog/wp-content/cache/tex_1f63c1ec2345db431cad4b44a538a808.png"  class="tex" align="absmiddle" title="x^4-x^3-6x^2=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionedyloirwzs')" id="Solutionedyloirwzs_button" value="+" />
				Solution
			</legend>
			<div id="Solutionedyloirwzs"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_7a9af5d3a3a54af6f4236ec98a48c2b7.png"  class="tex" align="absmiddle" title="\begin{align*}x^4-x^3-6x^2&#038;=0\\x^2(x^2-x-6)&#038;=0\\x^2(x-3)(x+2)&#038;=0\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_11d46d3750242ad0c8e9590f509febcc.png"  class="tex" align="absmiddle" title="x=0,3,-2" />.<br />

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3. <img src="http://watchmath.com/vlog/wp-content/cache/tex_76311cb90cd183f9d5a9a5feae122b42.png"  class="tex" align="absmiddle" title="2x^3+x^2-18x-9=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionkygqhuzksh')" id="Solutionkygqhuzksh_button" value="+" />
				Solution
			</legend>
			<div id="Solutionkygqhuzksh"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_02c961a22b1c1bc9d3dfe8369eb83ffb.png"  class="tex" align="absmiddle" title="\begin{align*}2x^3+x^2-18x-9&#038;=0\\(2x^3+x^2)-(18x+9)&#038;=0\\x^2(2x+1)-9(2x+1)&#038;=0\\(2x+1)(x^2-9)&#038;=0\\(2x+1)(x+3)(x-3)&#038;=0\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_ff8e48a29d83e5cab29b773ae3bca408.png"  class="tex" align="absmiddle" title="\textstyle x=-\frac{1}{2},-3,3" />.<br />

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4. <img src="http://watchmath.com/vlog/wp-content/cache/tex_43ac7624defdfbd09caa8450c0ec00b8.png"  class="tex" align="absmiddle" title="\frac{1}{x-1}+\frac{1}{x+2}=\frac{5}{4}" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutioncpotbrzerf')" id="Solutioncpotbrzerf_button" value="+" />
				Solution
			</legend>
			<div id="Solutioncpotbrzerf"><br />
Multiply both sides by <img src="http://watchmath.com/vlog/wp-content/cache/tex_5da9ddfc950cc04fb8150c335f250d2a.png"  class="tex" align="absmiddle" title="4(x-1)(x+2)" /> to get<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_d5ea39808477f0492cdffc14283a92b1.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
{\color{Red} 4(x-1)(x+2)}\left(\frac{1}{x-1}+\frac{1}{x+2}\right)&#038;={\color{Red}4(x-1)(x+2)}\frac{5}{4}\\<br />
4(x+2)+4(x-1)&#038;=5(x-1)(x+2)\\<br />
4x+8+4x-4&#038;=5(x^2+x-2)\\<br />
8x+4&#038;=5x^2+5x-10\\<br />
5x^2-3x-14&#038;=0\\<br />
5x^2-10x+7x-14&#038;=0\\<br />
(5x^2-10x)+(7x-14)&#038;=0\\<br />
5x(x-2)+7(x-2)&#038;=0\\<br />
(5x+7)(x-2)&#038;=0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_590414970d353b986668e5f7062f3690.png"  class="tex" align="absmiddle" title="\textstyle x=-\frac{7}{5},2" />.<br />

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5. <img src="http://watchmath.com/vlog/wp-content/cache/tex_2ec28c9e6fc1f7c1dd3735b34bbd645f.png"  class="tex" align="absmiddle" title="(x+5)^2-3(x+5)-10=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionmwilhwtyts')" id="Solutionmwilhwtyts_button" value="+" />
				Solution
			</legend>
			<div id="Solutionmwilhwtyts"><br />
Let <img src="http://watchmath.com/vlog/wp-content/cache/tex_2371436c3f5d99865ee22955a6fcf8f5.png"  class="tex" align="absmiddle" title="z=x+5" /> then the equation is equivalent to<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_f36ecdcdc36a54395fe3f334b9196b06.png"  class="tex" align="absmiddle" title="\begin{align*}z^2-3z-10&#038;=0\\(z-5)(z+2)&#038;=0\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_d1ad1c775317ee12b3cb1f7d86f590d8.png"  class="tex" align="absmiddle" title="z=5" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_fb4533826da5d8bfd7b65cddd28d463d.png"  class="tex" align="absmiddle" title="z=-2" />. It follows that <img src="http://watchmath.com/vlog/wp-content/cache/tex_30a0b0a37b62f45a6cda1a49522d017a.png"  class="tex" align="absmiddle" title="x+5=-2" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_a6680683daa4378030c99dfebc1aa29d.png"  class="tex" align="absmiddle" title="x+5=5" />. Solving these equations we have <img src="http://watchmath.com/vlog/wp-content/cache/tex_f81f32c2df1d9aabe69bbf4a4aa6096e.png"  class="tex" align="absmiddle" title="x=-7" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_1065700e28e0a76739a25ae46ed7bad4.png"  class="tex" align="absmiddle" title="x=0" />.<br />

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6. <img src="http://watchmath.com/vlog/wp-content/cache/tex_2beb77ea706b4d83c97277defee6fa6c.png"  class="tex" align="absmiddle" title="\left(\frac{x+1}{x}\right)^2+4\left(\frac{x}{x+1}\right)+3=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionqdrwtyrsjj')" id="Solutionqdrwtyrsjj_button" value="+" />
				Solution
			</legend>
			<div id="Solutionqdrwtyrsjj"><br />
Let <img src="http://watchmath.com/vlog/wp-content/cache/tex_b3ab634ed585060b0998a97b134e0dfb.png"  class="tex" align="absmiddle" title="x=\frac{x+1}{x}" />, then the equation is equivalent to<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_96ffe49b06e313a822d9f26de72cf46c.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
z^2+4z+3&#038;=0\\<br />
(z+1)(z+3)&#038;=0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_4179a823826d45c550e17b6bde300cc5.png"  class="tex" align="absmiddle" title="z=-1" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_33d8291ea1bcdd4824e2f03a72a366e9.png"  class="tex" align="absmiddle" title="z=-3" />. It follows that <img src="http://watchmath.com/vlog/wp-content/cache/tex_01aacadbb0a7b8da40325dce31d81ed2.png"  class="tex" align="absmiddle" title="\frac{x}{x+1}=-1" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_129802aa503bdea60c5cffd19ef5f22d.png"  class="tex" align="absmiddle" title="\frac{x}{x+1}=-3" />.<br />
From the first equation we have <img src="http://watchmath.com/vlog/wp-content/cache/tex_828642c51f266afe9e60b2dff3669ee9.png"  class="tex" align="absmiddle" title="x=-(x+1)" />. It follows that <img src="http://watchmath.com/vlog/wp-content/cache/tex_10d96ff61eb9ddec0fafe23ff267fe92.png"  class="tex" align="absmiddle" title="2x=-1" /> and hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_0c884f755cee2aac198d6ec5095de70f.png"  class="tex" align="absmiddle" title="x=-1/2" />.<br />
From the second equation we have <img src="http://watchmath.com/vlog/wp-content/cache/tex_70b39fb6faba25d99f43a1d7902e6e9a.png"  class="tex" align="absmiddle" title="x=-3(x+1)" />. It follows that <img src="http://watchmath.com/vlog/wp-content/cache/tex_7715f14716c178dabcba847432af4158.png"  class="tex" align="absmiddle" title="4x=-3" /> and hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_2d05fff4f01e71415efccabfbfad42f3.png"  class="tex" align="absmiddle" title="x=-3/4" />.<br />
Therefore <img src="http://watchmath.com/vlog/wp-content/cache/tex_0c884f755cee2aac198d6ec5095de70f.png"  class="tex" align="absmiddle" title="x=-1/2" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_2d05fff4f01e71415efccabfbfad42f3.png"  class="tex" align="absmiddle" title="x=-3/4" /> are the solution of the original equation.<br />

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7. <img src="http://watchmath.com/vlog/wp-content/cache/tex_2a8faba1c25f79fd60fa5fd425cf69bd.png"  class="tex" align="absmiddle" title="x^6-26x^3-27=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionzlzofafefx')" id="Solutionzlzofafefx_button" value="+" />
				Solution
			</legend>
			<div id="Solutionzlzofafefx"><br />
Let <img src="http://watchmath.com/vlog/wp-content/cache/tex_3f5a11803702d7cbcb32dcd98d69ac62.png"  class="tex" align="absmiddle" title="z=x^3" />, then the equation is equivalent to<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_3f52c2e29033cd0193738a7111f1b7f6.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
z^2-26z-27&#038;=0\\<br />
(z-27)(z+1)&#038;=0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_17480765311f3d19da012a5946b989f2.png"  class="tex" align="absmiddle" title="z=27" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_4179a823826d45c550e17b6bde300cc5.png"  class="tex" align="absmiddle" title="z=-1" />. It follows that <img src="http://watchmath.com/vlog/wp-content/cache/tex_7978c4b1f3e52891c25fc61a122ae601.png"  class="tex" align="absmiddle" title="x^3=27" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_5e2b063fa17abaf0fa19eeabe8f57482.png"  class="tex" align="absmiddle" title="x^3=-1" /> and these implies that <img src="http://watchmath.com/vlog/wp-content/cache/tex_2822a18d64bd1ae00860b944a8b250e2.png"  class="tex" align="absmiddle" title="x=3" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_f6df138b946cba79480d37c91bb7c4b5.png"  class="tex" align="absmiddle" title="x=-1" />.<br />

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8. <img src="http://watchmath.com/vlog/wp-content/cache/tex_a5b94120ea0188e371a7615505299c6b.png"  class="tex" align="absmiddle" title="2x+\sqrt{x+1}=8" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionjstsdapxzi')" id="Solutionjstsdapxzi_button" value="+" />
				Solution
			</legend>
			<div id="Solutionjstsdapxzi"><br />
Rewrite the equation as <img src="http://watchmath.com/vlog/wp-content/cache/tex_cead11855beaa41f5090873002e202f2.png"  class="tex" align="absmiddle" title="\sqrt{x+1}=8-2x" />. Square both sides, we have<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_81bfecf1eefcbb1ccbd220a0b9d4cbd2.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
x+1&#038;=(8-2x)^2\\<br />
x+1&#038;=64-32x+4x^2\\<br />
0&#038;=4x^2-33x+63\\<br />
0&#038;=4x^2-12x-21x+63\\<br />
0&#038;=4x(x-3)-21(x-3)\\<br />
0&#038;=(4x-21)(x-3)<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_88adfd3e419c5269a75396ca4eacdd63.png"  class="tex" align="absmiddle" title="x=21/4" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_2822a18d64bd1ae00860b944a8b250e2.png"  class="tex" align="absmiddle" title="x=3" /><br />
One can check that <img src="http://watchmath.com/vlog/wp-content/cache/tex_88adfd3e419c5269a75396ca4eacdd63.png"  class="tex" align="absmiddle" title="x=21/4" /> is not a solution of the original equation and <img src="http://watchmath.com/vlog/wp-content/cache/tex_c8e57d80844949c386d759299fed36e8.png"  class="tex" align="absmiddle" title="x=2" /> is a solution.<br />
Therefore <img src="http://watchmath.com/vlog/wp-content/cache/tex_c8e57d80844949c386d759299fed36e8.png"  class="tex" align="absmiddle" title="x=2" /> is the only solution.<br />

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9. <img src="http://watchmath.com/vlog/wp-content/cache/tex_1f5e5c25f7f049368464de4d50867cf6.png"  class="tex" align="absmiddle" title="x+2\sqrt{x-7}=10" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionqplhmfgdyp')" id="Solutionqplhmfgdyp_button" value="+" />
				Solution
			</legend>
			<div id="Solutionqplhmfgdyp"><br />
Rewrite the equation as <img src="http://watchmath.com/vlog/wp-content/cache/tex_7c2b915118d8f92c8551334dc0fd0a76.png"  class="tex" align="absmiddle" title="2\sqrt{x-7}=10-x" />. Square both sides of the equation to have<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_65f8ad8fafd790e09c00ec807c5598c5.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
4(x-7)&#038;=100-20x+x^2\\<br />
4x-28&#038;=x^2-2x+100\\<br />
0&#038;=x^2-6x+128<br />
\end{align*}" /><br />
The discriminant of the last equation is <img src="http://watchmath.com/vlog/wp-content/cache/tex_c460fc05ccbd7fe65ae32e852847e197.png"  class="tex" align="absmiddle" title="6^2-4\cdot1\cdot 128=36-512<0" />. Hence the equation has no solution.<br />

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10. <img src="http://watchmath.com/vlog/wp-content/cache/tex_aaa8d86a006ae18378bf4f086ae3cc53.png"  class="tex" align="absmiddle" title="\sqrt[3]{4x^2-4x}=x" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionmxallfmrjs')" id="Solutionmxallfmrjs_button" value="+" />
				Solution
			</legend>
			<div id="Solutionmxallfmrjs"><br />
Raise both sides to the third power to get <img src="http://watchmath.com/vlog/wp-content/cache/tex_d5b945601767fc25e2439a0b2067cc29.png"  class="tex" align="absmiddle" title="4x^2-4x=x^3" />. Now this equation is equivalent to<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_fab40dd1cde332a549b54dc6682ce080.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
x^3-4x^2+4x&#038;=0\\<br />
x(x^2-4x+4)&#038;=0\\<br />
x(x-2)^2&#038;=0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_1065700e28e0a76739a25ae46ed7bad4.png"  class="tex" align="absmiddle" title="x=0" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_c8e57d80844949c386d759299fed36e8.png"  class="tex" align="absmiddle" title="x=2" /> and one can easily verify that these two numbers are solutions of the original equation.<br />

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]]></content:encoded>
			<wfw:commentRss>http://watchmath.com/vlog/?feed=rss2&amp;p=1166</wfw:commentRss>
		<slash:comments>2</slash:comments>
		</item>
		<item>
		<title>Worked Problems (Quadratic Equations)</title>
		<link>http://watchmath.com/vlog/?p=1153</link>
		<comments>http://watchmath.com/vlog/?p=1153#comments</comments>
		<pubDate>Mon, 07 Sep 2009 04:03:16 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Algebra]]></category>
		<category><![CDATA[MA109]]></category>
		<category><![CDATA[completing the square]]></category>
		<category><![CDATA[Factoring]]></category>
		<category><![CDATA[Quadratic Equations]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1153</guid>
		<description><![CDATA[Factor the following trinomials 1. 2. 3. Write the following equations in the form (for example the equation can be written as ) 4. 5. Find all real solutions to the equation. 6. 7. 8. 9. 10. A rectangular bedroom is 7ft longer than it is wide. Its area is . What is the width [...]]]></description>
			<content:encoded><![CDATA[<p>Factor the following trinomials<br />
1. <img src="http://watchmath.com/vlog/wp-content/cache/tex_390925976909baa7a9e8040c8bdae9a3.png"  class="tex" align="absmiddle" title="x^2+8x+12" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionptkiloialh')" id="Solutionptkiloialh_button" value="+" />
				Solution
			</legend>
			<div id="Solutionptkiloialh"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_56233962334086e11b04695d961b2602.png"  class="tex" align="absmiddle" title="\begin{align*}x^2+8x+12&#038;=x^2+{\color{Red}2x+6x}+12\\&#038;=(x^2+2x)+(6x+12)\\&#038;=x(x+2)+6(x+2)\\&#038;=(x+2)(x+6)\end{align*}" /><br />

			</div>
		</fieldset><br />
2. <img src="http://watchmath.com/vlog/wp-content/cache/tex_6ee718c3d668e54c1166a46fb51a7393.png"  class="tex" align="absmiddle" title="4w^2-4w-3" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionicxujkapoy')" id="Solutionicxujkapoy_button" value="+" />
				Solution
			</legend>
			<div id="Solutionicxujkapoy"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_d8897b986bfe1fa381a97b485e229217.png"  class="tex" align="absmiddle" title="\begin{align*}4w^2-4w-3&#038;=4w^2+{\color{Red}2w-6w}-3\\&#038;=(4w^2+2w)-(6w+3)\\&#038;=2w(2w+1)-3(2w+1)\\&#038;=(2w-3)(2w+1)\end{align*}" /><br />

			</div>
		</fieldset><br />
3. <img src="http://watchmath.com/vlog/wp-content/cache/tex_84729f689902fc99fcbe9848892243d1.png"  class="tex" align="absmiddle" title="3x^2+1-4x" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionfbvfnhkzzu')" id="Solutionfbvfnhkzzu_button" value="+" />
				Solution
			</legend>
			<div id="Solutionfbvfnhkzzu"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_9ae0f83256819a30470dd425b3fc1186.png"  class="tex" align="absmiddle" title="\begin{align*}3x^2-4x+1&#038;=3x^2{\color{Red}-3x-x}+1\\&#038;=(3x^2-3x)-(x-1)\\&#038;=3x(x-1)-(x-1)\\&#038;=(3x-1)(x-1)\end{align*}" /><br />

			</div>
		</fieldset></p>
<p>Write the following equations in the form <img src="http://watchmath.com/vlog/wp-content/cache/tex_dc790e61aa6cb29fb1778da89f5bbbd9.png"  class="tex" align="absmiddle" title="(x+A)^2=B" /> (for example the equation <img src="http://watchmath.com/vlog/wp-content/cache/tex_a6fbff1d278f3872decae07a8a062658.png"  class="tex" align="absmiddle" title="x^2+2x-5=0" /> can be written as <img src="http://watchmath.com/vlog/wp-content/cache/tex_fc94f65d5c795ed2aa367a7dc601db94.png"  class="tex" align="absmiddle" title="(x+1)^2=6" />)</p>
<p>4. <img src="http://watchmath.com/vlog/wp-content/cache/tex_16a1681d7b7a962c9f4a8b3905360938.png"  class="tex" align="absmiddle" title="x^2-4x+2=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionsoncwzqfzc')" id="Solutionsoncwzqfzc_button" value="+" />
				Solution
			</legend>
			<div id="Solutionsoncwzqfzc"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_3311e17cc65fad81fa1f9106bbe61378.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
x^2-4x+2&#038;=0\\<br />
x^2-4x&#038;=-2\\<br />
{\color{Red} (x-2)^2-(-2)^2}&#038;=-2\\<br />
(x-2)^2-4&#038;=-2\\<br />
(x-2)^2&#038;=2<br />
\end{align*}" /><br />

			</div>
		</fieldset><br />
5. <img src="http://watchmath.com/vlog/wp-content/cache/tex_0c20506367bc0ed7ab2aee019a228557.png"  class="tex" align="absmiddle" title="x^2-5x+1=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionniflcovdej')" id="Solutionniflcovdej_button" value="+" />
				Solution
			</legend>
			<div id="Solutionniflcovdej"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_58d65cac0cc3a446dd80b1b9bc439839.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
x^2-5x+1&#038;=0\\<br />
x^2-5x&#038;=-1\\<br />
{\color{Red} \left(x-\frac{5}{2}\right)^2-\left(-\frac{5}{2}\right)^2}&#038;=-1\\<br />
\left(x-\frac{5}{2}\right)^2-\frac{25}{4}&#038;=-1\\<br />
\left(x-\frac{5}{2}\right)^2&#038;=\frac{21}{4}<br />
\end{align*}" /><br />

			</div>
		</fieldset></p>
<p>Find all real solutions to the equation.<br />
6. <img src="http://watchmath.com/vlog/wp-content/cache/tex_3a295988e9a27569080bd81d288c2383.png"  class="tex" align="absmiddle" title="x^2+30x+200=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionbjkxpxezxe')" id="Solutionbjkxpxezxe_button" value="+" />
				Solution
			</legend>
			<div id="Solutionbjkxpxezxe"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_a3bab380f75e444e282b39bb185f8056.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
x^2+30x+200&#038;=0\\<br />
x^2+{\color{Red}10x+20x}+200&#038;=0\\<br />
(x^2+10x)+(20x+200)&#038;=0\\<br />
x(x+10)+20(x+10)&#038;=0\\<br />
(x+20)(x+10)&#038;=0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_c7f93fcfc0a198dfbe2e2901579706ac.png"  class="tex" align="absmiddle" title="x+20=0" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_1cf415cbc616b34555f4e7645c7d1ad5.png"  class="tex" align="absmiddle" title="x+10=0" /> which implies that <img src="http://watchmath.com/vlog/wp-content/cache/tex_b9d738ccecab60f118a8857919afe684.png"  class="tex" align="absmiddle" title="x=-10" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_d5526e0f0edb03cdc0f2440d957f9831.png"  class="tex" align="absmiddle" title="x=-20" />.<br />

			</div>
		</fieldset><br />
7. <img src="http://watchmath.com/vlog/wp-content/cache/tex_3f68ae959c194c6ff819dbb01eb1689e.png"  class="tex" align="absmiddle" title="3x^2+7x+4=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionupsisphjvg')" id="Solutionupsisphjvg_button" value="+" />
				Solution
			</legend>
			<div id="Solutionupsisphjvg"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_064e1109d605c229d707edec75bc10ef.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
3x^2+7x+4&#038;=0\\<br />
3x^2+{\color{Red} 3x+4x}+4&#038;=0\\<br />
(3x^2+3x)+(4x+4)&#038;=0\\<br />
3x(x+1)+4(x+1)&#038;=0\\<br />
(3x+4)(x+1)&#038;=0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_afe90f13727780d631f89cf7405f31f3.png"  class="tex" align="absmiddle" title="3x+4=0" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_14d7db028aa7a52886b0829c138e3dea.png"  class="tex" align="absmiddle" title="x+1=0" /> which implies that <img src="http://watchmath.com/vlog/wp-content/cache/tex_2d05fff4f01e71415efccabfbfad42f3.png"  class="tex" align="absmiddle" title="x=-3/4" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_f6df138b946cba79480d37c91bb7c4b5.png"  class="tex" align="absmiddle" title="x=-1" />.<br />

			</div>
		</fieldset><br />
8. <img src="http://watchmath.com/vlog/wp-content/cache/tex_35a5944d82a238d279afd0443c0d6435.png"  class="tex" align="absmiddle" title="w^2=3(w-1)" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionmiprurgpuk')" id="Solutionmiprurgpuk_button" value="+" />
				Solution
			</legend>
			<div id="Solutionmiprurgpuk"><br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_b97b8db2575e12fde1b251cc3ff0ea73.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
w^2&#038;=3(w-1)\\<br />
w^2&#038;=3w-3\\<br />
w^2-3w&#038;=-3\\<br />
\left(w-\frac{3}{2}\right)^2-\left(-\frac{3}{2}\right)^2&#038;=-3\\<br />
\left(w-\frac{3}{2}\right)^2-\frac{9}{4}&#038;=-3\\<br />
\left(w-\frac{3}{2}\right)^2&#038;=-\frac{3}{4}<br />
\end{align*}" /><br />
Hence the equation has no solution.<br />
Remark: one can use determinant analysis to arrive at the some conclusion.<br />

			</div>
		</fieldset><br />
9. <img src="http://watchmath.com/vlog/wp-content/cache/tex_2b5c3511d21566d9fe7540a0487da39d.png"  class="tex" align="absmiddle" title="5x^2-7x+5=0" /><br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutionzwuktjhxjf')" id="Solutionzwuktjhxjf_button" value="+" />
				Solution
			</legend>
			<div id="Solutionzwuktjhxjf"><br />
Note that the discriminant of this equation is<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_f28e758c5411a1738f2f79487caa1069.png"  class="tex" align="absmiddle" title="D=(-7)^2-4\cdot 5\cdot 5=49-100=-51" />. Hence the equation has no solution.<br />

			</div>
		</fieldset></p>
<p>10. A rectangular bedroom is 7ft longer than it is wide. Its area is <img src="http://watchmath.com/vlog/wp-content/cache/tex_35949432d7bbdee549e774a71fb89be6.png"  class="tex" align="absmiddle" title="228 \text{ft}^2" />. What is the width of the room?<br />
<fieldset class="spoiler">
			<legend>
				<input type="button" onclick="tiny_spoiler('Solutioncdvvlnktxg')" id="Solutioncdvvlnktxg_button" value="+" />
				Solution
			</legend>
			<div id="Solutioncdvvlnktxg"><br />
Let <img src="http://watchmath.com/vlog/wp-content/cache/tex_e18248211f60ca7f808cd22305f2f64b.png"  class="tex" align="absmiddle" title="w" /> be the width of the bedroom. Then the length of the other side is <img src="http://watchmath.com/vlog/wp-content/cache/tex_5e8c4e115cd2dae12ce22cb94828c383.png"  class="tex" align="absmiddle" title="w+4" />. Therefore the area of the room is<br />
<center><img src="http://watchmath.com/vlog/wp-content/cache/tex_4a7c548bf2306597e90023164795a099.png"  class="tex" align="absmiddle" title="w(w+7)=228" /></center><br />
Now<br />
<img src="http://watchmath.com/vlog/wp-content/cache/tex_aacf9bb6ed2d0fbe7457c5f9f7895a5e.png"  class="tex" align="absmiddle" title="\begin{align*}<br />
w(w+7)&#038;=228\\<br />
w^2+7w-228&#038;=0\\<br />
w^2+19w-12w-228&#038;=0\\<br />
(w^2+19w)-(12w+228)&#038;=0\\<br />
w(w+19)-12(w+19)&#038;=0\\<br />
(w-12)(w+19)&#038;=0<br />
\end{align*}" /><br />
Hence <img src="http://watchmath.com/vlog/wp-content/cache/tex_876763c98e52e24aa7abe9875509a5e9.png"  class="tex" align="absmiddle" title="w=12" /> or <img src="http://watchmath.com/vlog/wp-content/cache/tex_8188524a36b55d5e0830297b75df1be6.png"  class="tex" align="absmiddle" title="w=-19" />. But since the width must be a positive number then the width is 12 ft.<br />

			</div>
		</fieldset></p>
]]></content:encoded>
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		<item>
		<title>Worksheet 8 (Graphs of Equations)</title>
		<link>http://watchmath.com/vlog/?p=1042</link>
		<comments>http://watchmath.com/vlog/?p=1042#comments</comments>
		<pubDate>Sun, 23 Aug 2009 20:01:27 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Algebra]]></category>
		<category><![CDATA[MA109]]></category>
		<category><![CDATA[circle]]></category>
		<category><![CDATA[Graph of Equations]]></category>
		<category><![CDATA[plot graph]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1042</guid>
		<description><![CDATA[Determine which given points are on the graph of the equation. 1. : (1,0),(0,1),(3,2) 2. : (0,-2),(1,-2),(2,-2) Find the - and - intercepts of the graph of the equation. 3. 4. Make a table of values and sketch the graph of the equation. 5. 6. 7. Find an equation of the circle that satisfies the [...]]]></description>
			<content:encoded><![CDATA[<p>Determine which given points are on the graph of the equation.<br />
1. <img src="http://watchmath.com/vlog/wp-content/cache/tex_b11396c4e676869a46377dd2c01b7208.png"  class="tex" align="absmiddle" title="y=\sqrt{x+1}" />: (1,0),(0,1),(3,2)<br />
2. <img src="http://watchmath.com/vlog/wp-content/cache/tex_fbedbf335450091bf1701ce837402aca.png"  class="tex" align="absmiddle" title="x^2+xy+y^2=4" />: (0,-2),(1,-2),(2,-2)</p>
<p>Find the <img src="http://watchmath.com/vlog/wp-content/cache/tex_90a0f149844a5d36c7722b5dc3fe6147.png"  class="tex" align="absmiddle" title="x" />- and <img src="http://watchmath.com/vlog/wp-content/cache/tex_2737227b9b28a8b5f3d0fc7f042a7915.png"  class="tex" align="absmiddle" title="y" />- intercepts of the graph of the equation.<br />
3. <img src="http://watchmath.com/vlog/wp-content/cache/tex_4b0f7400410d351b6342a281a5d28c0e.png"  class="tex" align="absmiddle" title="y=x^2-5x+6" /><br />
4. <img src="http://watchmath.com/vlog/wp-content/cache/tex_382349a1786c595965617194ea88a1d6.png"  class="tex" align="absmiddle" title="y-2xy=2x=1" /></p>
<p>Make a table of values and sketch the graph of the equation.<br />
5. <img src="http://watchmath.com/vlog/wp-content/cache/tex_f0cc44e591b169edb777aca3aa4fd54d.png"  class="tex" align="absmiddle" title="y=2x" /><br />
6. <img src="http://watchmath.com/vlog/wp-content/cache/tex_8fc6671a8c859cd5e7d2c7cdf9e9b26e.png"  class="tex" align="absmiddle" title="y=x^2+2" /><br />
7. <img src="http://watchmath.com/vlog/wp-content/cache/tex_40c255c27242af8163e68088c91098ee.png"  class="tex" align="absmiddle" title="x=|y|" /></p>
<p>Find an equation of the circle that satisfies the given conditions.<br />
8. Center <img src="http://watchmath.com/vlog/wp-content/cache/tex_61445ac5d51b237efa3297c9889d2db2.png"  class="tex" align="absmiddle" title="(-1,-4)" />; radius 8<br />
9. Endpoints of a diameter are <img src="http://watchmath.com/vlog/wp-content/cache/tex_2a7d769078133613f58425ebe44f9a56.png"  class="tex" align="absmiddle" title="P(-1,1)" /> and <img src="http://watchmath.com/vlog/wp-content/cache/tex_dae9b2e566cdaa537190a95436681294.png"  class="tex" align="absmiddle" title="Q(5,5)" /></p>
<p>10. The equation <img src="http://watchmath.com/vlog/wp-content/cache/tex_02d9ebf29837587206ef0218f36dca6d.png"  class="tex" align="absmiddle" title="x^2+y^2+6y+2=0" /> is an equation of a circle. Find the center and radius of the circle.</p>
]]></content:encoded>
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		<slash:comments>0</slash:comments>
		</item>
		<item>
		<title>Worksheet 5 (Inequalities)</title>
		<link>http://watchmath.com/vlog/?p=1022</link>
		<comments>http://watchmath.com/vlog/?p=1022#comments</comments>
		<pubDate>Sun, 23 Aug 2009 11:17:48 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Algebra]]></category>
		<category><![CDATA[MA109]]></category>
		<category><![CDATA[Inequalities]]></category>
		<category><![CDATA[Solving Inequalities]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1022</guid>
		<description><![CDATA[Solve the linear inequality. Express the solution using interval notation. 1.]]></description>
			<content:encoded><![CDATA[<p>Solve the linear inequality. Express the solution using interval notation.<br />
1. <img src="http://watchmath.com/vlog/wp-content/cache/tex_7cee9a9c84ad5112f549baf94d39c448.png"  class="tex" align="absmiddle" title="3x+11<5" /><br />
2. <img src="http://watchmath.com/vlog/wp-content/cache/tex_050a1ea15037840474f24f7b76474061.png"  class="tex" align="absmiddle" title="\frac{2}{5}x+1<\frac{1}{5}-2x" /><br />
3. <img src="http://watchmath.com/vlog/wp-content/cache/tex_9c0a7487569eefbf478f799fe2ff23a9.png"  class="tex" align="absmiddle" title="2(7x-3)\leq 12x+16" /><br />
4. <img src="http://watchmath.com/vlog/wp-content/cache/tex_4f90e74bbab2f195f971ec0f5f78e9ca.png"  class="tex" align="absmiddle" title="5\leq 3x-4\leq 14" /><br />
5. <img src="http://watchmath.com/vlog/wp-content/cache/tex_07bc2d8aa288d01b661b8db4c43a9a47.png"  class="tex" align="absmiddle" title="-\frac{1}{2}<\frac{4-3x}{5}\leq \frac{1}{4}" /></p>
<p>Solve the nonlinear inequality. Express the solution using interval notation.<br />
6.<img src="http://watchmath.com/vlog/wp-content/cache/tex_56873f41f6f760a0124d90aea7299797.png"  class="tex" align="absmiddle" title="(x-5)(x+4)\geq 0" /><br />
7. <img src="http://watchmath.com/vlog/wp-content/cache/tex_e4e79d68dcd4440edbeb67f80a1ffc8d.png"  class="tex" align="absmiddle" title="5x^2+3x\geq 3x^2+2" /><br />
8. <img src="http://watchmath.com/vlog/wp-content/cache/tex_cbe19538adab27637e9891daa8d1b4b0.png"  class="tex" align="absmiddle" title="(x+2)(x-1)(x-3)\leq 0" /><br />
9. <img src="http://watchmath.com/vlog/wp-content/cache/tex_4d99d0c2bff15bab69e70b7cad124185.png"  class="tex" align="absmiddle" title="\frac{2x+6}{x-2}<0" /><br />
10. <img src="http://watchmath.com/vlog/wp-content/cache/tex_c92d8fd168171aaa73e8adec3c73845f.png"  class="tex" align="absmiddle" title="\frac{x}{x+1}>3x&#8221; /><br />
<!--noadsense--></p>
]]></content:encoded>
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		<slash:comments>5</slash:comments>
		</item>
		<item>
		<title>Worksheet 4 (Other Types of Equations)</title>
		<link>http://watchmath.com/vlog/?p=1019</link>
		<comments>http://watchmath.com/vlog/?p=1019#comments</comments>
		<pubDate>Sun, 23 Aug 2009 11:05:06 +0000</pubDate>
		<dc:creator>watchmath</dc:creator>
				<category><![CDATA[Algebra]]></category>
		<category><![CDATA[MA109]]></category>
		<category><![CDATA[Equation of Quadratic Type]]></category>
		<category><![CDATA[Equation with Radicals]]></category>
		<category><![CDATA[Factoring]]></category>

		<guid isPermaLink="false">http://watchmath.com/vlog/?p=1019</guid>
		<description><![CDATA[Find all real solutions of the equation. 1. 2. 3. 4. 5. 6. 7. 8. 9. 10.]]></description>
			<content:encoded><![CDATA[<p>Find all real solutions of the equation.<br />
1. <img src="http://watchmath.com/vlog/wp-content/cache/tex_5acedb4314f39db9f2222aa63aa17f5f.png"  class="tex" align="absmiddle" title="x^4+64x=0" /><br />
2. <img src="http://watchmath.com/vlog/wp-content/cache/tex_1f63c1ec2345db431cad4b44a538a808.png"  class="tex" align="absmiddle" title="x^4-x^3-6x^2=0" /><br />
3. <img src="http://watchmath.com/vlog/wp-content/cache/tex_76311cb90cd183f9d5a9a5feae122b42.png"  class="tex" align="absmiddle" title="2x^3+x^2-18x-9=0" /><br />
4. <img src="http://watchmath.com/vlog/wp-content/cache/tex_43ac7624defdfbd09caa8450c0ec00b8.png"  class="tex" align="absmiddle" title="\frac{1}{x-1}+\frac{1}{x+2}=\frac{5}{4}" /><br />
5. <img src="http://watchmath.com/vlog/wp-content/cache/tex_2ec28c9e6fc1f7c1dd3735b34bbd645f.png"  class="tex" align="absmiddle" title="(x+5)^2-3(x+5)-10=0" /><br />
6. <img src="http://watchmath.com/vlog/wp-content/cache/tex_2beb77ea706b4d83c97277defee6fa6c.png"  class="tex" align="absmiddle" title="\left(\frac{x+1}{x}\right)^2+4\left(\frac{x}{x+1}\right)+3=0" /><br />
7. <img src="http://watchmath.com/vlog/wp-content/cache/tex_2a8faba1c25f79fd60fa5fd425cf69bd.png"  class="tex" align="absmiddle" title="x^6-26x^3-27=0" /><br />
8. <img src="http://watchmath.com/vlog/wp-content/cache/tex_a5b94120ea0188e371a7615505299c6b.png"  class="tex" align="absmiddle" title="2x+\sqrt{x+1}=8" /><br />
9. <img src="http://watchmath.com/vlog/wp-content/cache/tex_1f5e5c25f7f049368464de4d50867cf6.png"  class="tex" align="absmiddle" title="x+2\sqrt{x-7}=10" /><br />
10. <img src="http://watchmath.com/vlog/wp-content/cache/tex_aaa8d86a006ae18378bf4f086ae3cc53.png"  class="tex" align="absmiddle" title="\sqrt[3]{4x^2-4x}=x" /><br />
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